How much quicklime can be obtained from 200 kg of limestone containing 20% of impurities

How much quicklime can be obtained from 200 kg of limestone containing 20% of impurities, if the product yield is 85% of the theoretically possible.

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

When 1 mol of limestone is decomposed, 1 mol of gaseous carbon dioxide is synthesized.

This also synthesizes 1 mol of calcium oxide

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 200,000 x 0.8 / 100 = 1,600 mol;

Taking into account the yield in the course of the reaction, 1,600 x 0.85 = 1,360 mol of calcium oxide will be synthesized.

N CaO = 1,360 mol;

Its weight will be:

M CaO = 40 + 16 = 56 grams / mol;

m CaO = 56 x 1 360 = 76.16 kg;