How much salt was formed when 400 g of sodium hydroxide interacted with sulfuric acid?

univerkov | February 11, 2021 | education

Reaction equation: 2NaOH + H2SO4 = Na2SO4 + 2H2O
According to the periodic table, we determine the molar mass of sodium hydroxide M = 23 + 16 + 1 = 40 g / mol. The molar mass of sodium sulfate M = 23 * 2 + 32 + 16 * 4 = 142 g / mol.
Find the amount of sodium hydroxide: n = m / M = 400 g / 40 g / mol = 10 mol.
According to the reaction from 2 mol of hydroxide, 1 mol of salt is obtained, which means 10/2 = n (salt) / 1. n (salt) = 5 mol.
Find the mass of salt: m = n * M = 5 mol * 142 g / mol = 710 g.
Answer: 710 g of salt is formed.

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