How much semi-aqueous gypsum CaSO4 * 0.5H2O will be obtained after heat treatment of 10 tons of gypsum

How much semi-aqueous gypsum CaSO4 * 0.5H2O will be obtained after heat treatment of 10 tons of gypsum CaSO4 * 2H2O? I know that the reaction proceeds according to the formula: CaSO4 * 2H2O = CaSO4 * 0.5H2O + 1.5 H2O.

CaSO4 * 2H2O = CaSO4 * 0.5H2O + 1.5 H2O.
Мcaso4 2h4o = 40 + 32 + 4 * 16 + 2 (2 * 1 + 16) = 172 grams / mol.
Mcaso4 0.5h4o = 40 + 32 + 4 * 16 + 0.5 (2 * 1 + 16) = 145 grams / mol.
can be read immediately in tons
145 * 10/172 = 8.43 t.



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