How much should one move vertically from the surface of the earth in order for the atmospheric pressure

How much should one move vertically from the surface of the earth in order for the atmospheric pressure to decrease by 133.3 Pa? How much will it decrease with a rise of 150 m.

Given:

P1 = 133.3 Pascal – pressure value;

h = 150 meters – height above the ground;

g = 10 N / kg (Newton per kilogram) – acceleration due to gravity (rounded off value);

ro = 1.3 kg / m3 (kilogram per cubic meter) – air density (under normal conditions).

It is required to determine h0 (meter) – how much it should move from the Earth’s surface in order for the pressure to decrease by the value P1, and also P (Pascal) – how much the pressure will decrease when climbing to a height h.

h0 = P1 / (ro * g) = 133.3 / (1.3 * 10) = 133.3 / 13 = 10.3 meters (the result has been rounded to one decimal place).

Then:

P = P1 * (h / h0) = 133.3 * 150 / 10.3 = 1941 Pascal.

Answer: h0 = 10.3 meters, P = 1941 Pascal.