How much sludge can be obtained if the gas formed during the combustion of ethane

| June 19, 2021 | education

How much sludge can be obtained if the gas formed during the combustion of ethane with a volume of 448 cm3 is passed through an excess of lime water?

The gas formed during the combustion of ethane is carbon dioxide (CO2), lime water is Ca (OH) 2, the sediment is calcium carbonate CaCO3
Let’s write down the reaction schemes and arrange the coefficients:
2С2H6 + 7O2 = 4CO2 + 6H2O
CO2 + Ca (OH) 2 = CaCO3 + H2O
Let us determine the amount of ethane substance n (fl) = V (fl) / Vm, where:
Vm – molar volume, Vm = 22.4 l / mol
V (fl) – volume of ethane, Vet = 448 cm3 = 0.448 l
n (et) = 0.448 / 22.4 = 0.02 mol
It can be seen from the reaction schemes that the amount of CO2 substance is n (CO2) = 2n (et) = n (CaCO3), thus the amount of calcium carbonate substance n (CaCO3) = 2n (et) = 2 * 0.02 = 0.04 mol …
Determine the mass of CaCO3 – m (CaCO3) = n (CaCO3) * M (CaCO3), where M (CaCO3) = 100 g / mol is the molar mass of CaCO3
m (CaCO3) = 0.04 * 100 = 4 g



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