How much sludge is formed when enough magnesium chloride is added to 34g silver nitrate?

univerkov | August 22, 2021 | education

Reaction equation:
MgCl + 2AgNO3 = Mg (NO3) 2 + 2AgCl.
1) Find the molar mass of silver nitrate: 108 + 14 + 16 * 3 = 170.
2) Find the amount of silver nitrate substance. To do this, divide the mass of nitrate by its molar mass: 0.2 mol.
3) According to the reaction equation, there are two moles of silver chloride for two moles of silver nitrate. This means that the amount of silver chloride substance is 0.2 mol.
4) The molar mass of the sediment is: 108 + 35.5 = 143.5.
5) Weight of silver chloride: 143.5 * 0.2 = 28.7 g – answer.

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