How much SO2 will be released during the combustion of 124 liters of hydrogen sulfide?

The combustion reaction of hydrogen sulfide is described by the following chemical reaction equation:

H2S + 3/2 O2 = H2O + SO2;

Hydrogen sulfide and sulfur dioxide contain one sulfur atom. Therefore, from one mole of hydrogen sulfide, one mole of sulfur dioxide can be obtained.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Therefore, 124 liters of sulfur dioxide can be obtained from 124 liters of hydrogen sulfide.



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