How much sodium hydroxide is needed to react with 37.5 g of aminoacetic acid?

To solve the problem, it is necessary to compose the reaction equation:
CH2 (NH2) – COOH + NaOH = CH2 (NH2) – COONa + H2O – exchange reaction, the sodium salt of aminoacetic acid is formed;
Let’s calculate the molar masses of substances:
M (aminoox to-you) = 70 g / mol;
M (NaOH) = 39.9 g / mol;
Determine the number of moles of aminoacetic acid, sodium hydroxide:
Y (aminoox to-you) = m / M = 37.5 / 70 = 0.535 mol;
According to the reaction equation, the amounts of moles of aminoacetic acid and sodium hydroxide are equal (1 mol each), thus Y (NaOH) = 0.535 mol;
We find the mass of sodium hydroxide by the formula:
m (NaOH) = Y * M = 0.535 * 39.9 = 21.34 g.
Answer: the mass of sodium hydroxide is 21.34 g.