How much sodium hydroxide is required to react with 4.9 g of sulfuric acid?

m (H2SO4) = 4.9 g.
Determine the amount of sodium hydroxide that will react. We write down the solution.
We compose the reaction equation.
2NaOH + H2SO4 = Na2SO4 + 2H2O
First, find the amount of sulfuric acid using the following formula.
n = m / M.
Where m is the mass of the substance.
M is the molar mass of the substance.
n is the amount of substance.
Find the molar mass of sulfuric acid.
M (H2SO4) = 1 * 2 + 32 + 16 * 4 = 2 + 32 + 64 = 98 g / mol.
n = 4.9 / 98 = 0.05 mol.
Further, according to the reaction equation, we find the amount of sodium hydroxide substance.
X mol NaOH – 0.05 mol H2SO4
2 mol NaOH – 1 mol H2SO4
X = 2 * 0.05: 1 = 0.1 mol.
Answer: 0.1 mol NaOH.