How much sugar will remain at the bottom of the vessel when 650 g of its saturated solution is evaporated?

Data: mnr – weight of saturated solution of sucrose (mnr = 650 g); the water solubility of sucrose is 211.5 g / 100 ml or 211.5 g / 100 g.

1) The mass of sucrose solution and 100 g of water: mС12Н22О11 + mH2O = 211.5 + 100 = 311.5 g.

2) The ratio of the masses of saturated solution and sucrose: k = 311.5 / 211.5 ≈ 1.473 p.

3) The mass of sucrose in a saturated solution: mх = mnr / k = 650 / 1.473 ≈ 441.3 g.

Answer: 441.3 g of sucrose should have remained at the bottom.