How much sulfur oxide 4 can be obtained from 32 g of sulfur if the oxidation state of sulfur is 80%

How much sulfur oxide 4 can be obtained from 32 g of sulfur if the oxidation state of sulfur is 80% of the theoretically possible?

Let’s implement the solution:
1. By the condition of the problem, we write the equation:
m = 32 g. X g. -?
S + O2 = SO2 – the reaction of the compound, sulfur oxide was obtained (4);
2. Let’s make the calculations:
M (S) = 32 g / mol;
M (SO2) = 64 g / mol.
3. Find the theoretical mass of sulfur:
W = m (practical) / m (theoretical) * 100;
m (S) = 0.80 * 32 = 25.6 g. hence, Y (S) = m / M = 25.6 / 32 = 0.8 mol;
Y (SO2) = 0.8 mol since the amount of these substances according to the equation is equal to 1 mol.
4. Determine the mass of the product:
m (SO2) = Y * M = 0.8 * 64 = 51.2 g.
Answer: in the process of oxidation, sulfur oxide with a mass of 51.2 g was obtained.