How much sulfur was consumed if, when it interacted with iron, 44 g of iron sulfide was obtained (2)?

Let’s execute the solution:

According to the condition of the problem, we write down the equation of the process:
X g -? m = 44 g

S + Fe = FeS – compounds, iron sulfide is released (2);

Calculations by formulas:
M (S) = 32 g / mol;

M (FeS) = 87.6 g / mol.

Determine the amount of salt, if the mass is known:
Y (FeS) = m / M = 44 / 87.6 = 0.5 mol.

Y (S) = 0.5 mol since the amount of substances is 1 mol.

We find the mass of the original substance:
m (S) = Y * M = 0.5 * 32 = 16 g

Answer: you need sulfur weighing 16 g