How much sulfuric acid is required to react with 34 g of zinc hydroxide?

1. Let’s compose the equation for the reaction of sulfuric acid and zinc hydroxide:

H2SO4 + Zn (OH) 2 = ZnSO4 + 2H2O;

2.Calculate the chemical amount of zinc hydroxide:

n (Zn (OH) 2) = m (Zn (OH) 2): M (Zn (OH) 2);

M (Zn (OH) 2) = 65 + 2 * 17 = 99 g / mol;

n (Zn (OH) 2) = 34: 99 = 0.3434 mol;

3.determine the amount of sulfuric acid:

n (H2SO4) = n (Zn (OH) 2) = 0.3434 mol;

4.calculate the mass of the required acid:

m (H2SO4) = n (H2SO4) * M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

m (H2SO4) = 0.3434 * 98 = 33.65 g.

Answer: 33.65 g.