How much sulfuric acid is required to react with 34 g of zinc hydroxide?
July 29, 2021 | education|
1. Let’s compose the equation for the reaction of sulfuric acid and zinc hydroxide:
H2SO4 + Zn (OH) 2 = ZnSO4 + 2H2O;
2.Calculate the chemical amount of zinc hydroxide:
n (Zn (OH) 2) = m (Zn (OH) 2): M (Zn (OH) 2);
M (Zn (OH) 2) = 65 + 2 * 17 = 99 g / mol;
n (Zn (OH) 2) = 34: 99 = 0.3434 mol;
3.determine the amount of sulfuric acid:
n (H2SO4) = n (Zn (OH) 2) = 0.3434 mol;
4.calculate the mass of the required acid:
m (H2SO4) = n (H2SO4) * M (H2SO4);
M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;
m (H2SO4) = 0.3434 * 98 = 33.65 g.
Answer: 33.65 g.
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