How much sulfuric acid should be taken to neutralize a solution containing 40 g of potassium hydroxide?

Given:
2KOH + H2SO4 = K2SO4 + 2H2O
m (2KOH) -40g
To find:
m (H2SO4) -?
Decision:
x n. 40g H (H2SO4) = 98g
x = 40 * 114 \ 98 = 46/53 g
Answer: m (H2SO4) = 46.53g



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