How much sulfuric acid should be taken to neutralize a solution containing 40 g of potassium hydroxide?

univerkov | November 28, 2020 | education

Given
m (KOH) = 40 g
m (H2SO4) -?
Decision
1.Write the reaction equation:
2KOH + H2SO4 = K2SO4 + 2H2O
2. find the amount of substance by the formula n = m / M, where n is the amount of the substance, m is the mass of the substance, M is the molar mass of the substance
n (KOH) = 40/56 = 0.714 mol
3 the amount of sulfuric acid will be half as much (from the reaction equation)
n (H2SO4) = 0.714 / 2 = 0.357 mol
4. find the mass of acid by the formula m = n * M
m (H2SO4) = 0.357 * 98 = 35 g
Answer: the mass of sulfuric acid is 35 g.

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