How much the potential energy of a body weighing 2 kg has changed when it falls from a height of 10 m to a height of 20 m.

m = 2 kilograms – body weight;

H1 = 20 meters – initial body height;

H2 = 10 meters – final body height;

g = 10 N / kg – acceleration of gravity.

It is required to determine the change in potential energy dE (Joule) with a change in body height from H1 to H2.

dE = E1 – E2 = m * g * H1 – m * g * H2 = m * g * (H1 – H2) = 2 * 10 * (20 – 10) = 2 * 10 * 10 = 20 * 10 = 200 Joules …

Answer: the potential energy of the body will decrease by 200 Joules.