How much video memory is required to store four pages of an image, if the color depth is 32

How much video memory is required to store four pages of an image, if the color depth is 32, and the resolution of the monitor is 1024×768 pixels

First, let’s determine the total number of pixels in the image on one page.

We multiply the dimensions of the monitor among ourselves.

1024 * 768 = 786432.

Since in total you need to store 4 pages with images, the total number of pixels on them will be equal to:

786432 * 4 = 3145728 pixels.

We find the information volume of one pixel using the following formula:

N = 2 ^ i

32 = 2 * 2 * 2 * 2 * 2.

i = 5.

Thus, the total amount of images on 4 pages will be:

3145728 * 5 = 15728640 bits.

We translate the amount of information into kilobytes.

15728640 / (8 * 1024) = 15728640/8192 = 1920 KB.

Answer: 1920 KB.