How much video memory is required to store two pages of an image, provided
How much video memory is required to store two pages of an image, provided that the display resolution is 800 * 600 pixels, and the number of colors used is 256? Express the result in Kbytes.
First, let’s determine the total number of pixels in the image on one page.
We multiply the dimensions of the image with each other.
800 * 600 = 480,000
Since there are 2 pages with images in total, the total number of pixels on them will be equal to:
480,000 * 2 = 960,000.
We find the information volume of one pixel using the following formula:
N = 2i
256 = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2.
i = 8.
Thus, the total volume of the image will be:
960,000 * 8 = 7,680,000 bits.
We translate this value into kilobytes.
7680000 / (8 * 1024) = 7680000/8192 = 937.5 KB.
Answer: 937.5 KB.