How much video memory (KB) is required to store two pages of an image

How much video memory (KB) is required to store two pages of an image, provided that the display resolution is 640x 480, and the color depth is 24.

First, you need to determine the total number of pixels in one image.

To do this, we multiply its sizes among ourselves.

We get:

640 * 480 = 307200 pixels.

Since it is necessary to store 2 images, the total number of pixels in them will be:

307,200 * 2 = 614,400 pixels.

We find the amount of required video memory.

To do this, multiply the total number of pixels in the image by the color depth.

We get:

614400 * 24 = 14745600 bits.

When translated into bytes, we get:

14745600/8 = 1843200 bytes.

In Kilobytes it will be:

1843200/1024 = 1800 KB.

Answer: 1800 Kb.