How much volume 0.25 mol of NH3 will take under normal conditions. What is its mass?

V = Vm * n
V = 22.4 L / mol * 0.25 = 5.6 L
m = M * n
M = 14 + 3 = 17 g / mol
m = 17 * 0.25 = 4.25 g
Answer: the volume will take 17 grams / mol. And its mass will be 4.25 g.



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