How much volume is required for a balloon filled with helium to lift a person weighing 80 kg in a 50 kg basket?

m1 = 50 kg.
m2 = 80 kg.
g = 9.8 m / s ^ 2.
ρ = 0.17847 kg / m³.
V -?
Two forces act on the balloon with the basket: the force of gravity Ft directed vertically downward and the force of Archimedes Farkh vertically upward. In order for the ball to begin to rise, the force of Archimedes Farkh must be no less than the force of gravity Ft.
Farch ≥ Ft.
Fт = (m1 + m2) * g, where m1 is the mass of the basket, m2 is the mass of a person, g is the acceleration of gravity.
Farch = ρ * g * V, where ρ is the density of helium, V is the volume of the sphere.
ρ * g * V = (m1 + m2) * g.
ρ * V = (m1 + m2).
V = (m1 + m2) / ρ.
V = (50 kg + 80 kg) / 0.17847 kg / m³ = 22412.7 m³.
Answer: the volume of the sphere must be V ≥ 22412.7 m³.