How much water can be heated by 10 degrees Celsius, giving it 4.2 × 10 (3) J of heat?

To solve the problem, we will use the formula: Q = C * m * (t1-t2) where Q is the amount of heat, C is the specific heat (4.2 KJ / kg * deg), m is the mass, t1 and t2 are the initial and final temperatures. In this case t1-t2 = 10 Then we get:
m = Q / c * (t1-t2) = 4.2 * 10 ^ 3 / 4.2 * 10 ^ 3 * 10 = 1/10 = 0.1 kg.



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