How much water can be heated from 20 ° C to boiling by transferring to it the amount of heat 16.8 kJ?

univerkov | January 2, 2021 | education

Given:
t1 = 20 ° C
tboil = 100 ° C
Q = 16.8 kJ = 16800 J
c = 4200 J / kg * ° C
Find: m-?
Decision:
Formulas:
Q = cm * (tkip-t1)
m = Q / (c (tboil-t1))
m = 16800 J / 4200 J / kg * ° C * (100 ° C-20 ° C) = 16800 J / 4200 J / kg * ° C * 80 ° C = 0.05 kg
Answer: 0.05 kg

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