How much water can be heated from 25 degrees to a boil, transferring it an amount of heat equal to 188 kJ?

To estimate the amount of water heated to boiling, we use the formula: Q = Sv * m * (tк – t), whence we express: m = Q / (Sv * (tк – t)).

Values of variables and constants: Q – transferred heat (Q = 188 kJ = 188 * 10 ^ 3 J); Sv – specific heat capacity of water (Sv = 4200 J / (kg * K)); tк – temperature of the beginning of boiling (tк = 100 ºС); t – temperature before heat transfer (t = 25 ºС).

Calculation: m = Q / (Sv * (tk – t)) = 188 * 10 ^ 3 / (4200 * (100 – 25)) = 0.597 kg.

Answer: You can heat 0.597 kg of water.