# How much water can be raised from a well 200 m deep within 2 hours if the power of the installation

How much water can be raised from a well 200 m deep within 2 hours if the power of the installation is 75 kW and its efficiency is 90%?

Data: h (borehole depth) = 200 m; t (the duration of the rise of water from the well) = 2 hours (7200 s); Nu (installation power) = 75 kW (75 * 103 W); η (installation efficiency) = 90% (0.9).

Reference values: g (acceleration due to gravity) = 9.81 m / s2; ρw (density of the lifted water) = 1000 kg / m3.

The mass of water raised from the well is determined by the formula: η = Nf / Nу = (A / t) / Nу = m * g * h / (Nу * t), whence m = Nу * t * η / (g * h).

Calculation: m = 75 * 103 * 7200 * 0.9 / (9.81 * 200) = 247706 kg ≈ 248 tons.

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