How much water can you heat from 10 to 50 degrees if you transfer to it all the energy released

How much water can you heat from 10 to 50 degrees if you transfer to it all the energy released during the combustion of kerosene weighing 10 g? Specific heat of combustion of kerosene 46 MJ / kg

Initial data: t1 (water temperature before heating) = 10 ºС; t2 (water temperature after heating) = 50 ºС; m2 (mass of burnt kerosene) = 10 g or 0.01 kg; no heat loss.
Reference data: q (specific heat of combustion of kerosene) = 46 MJ / kg = 46 * 10 ^ 6 J / kg; C (specific heat of water) = 4200 J / (kg * K).
We calculate the mass of water from the ratio:
С * m1 * (t2 – t1) = q * m2, whence m1 = q * m2 / (С * (t2 – t1)).
Let’s do the calculation:
m1 = 46 * 10 ^ 6 * 0.01 / (4200 * (50 – 10)) = 2.738 kg.