How much water is heated to 80 degrees Celsius when burning 200 grams of alcohol.

univerkov | August 8, 2021 | education

These tasks: Δt (required change in water temperature) = 80 ºС; m2 (mass of burned alcohol) = 200 g (0.2 kg).

Reference values: Sv (specific heat capacity of water) = 4200 J / (kg * K); q (specific heat of combustion of alcohol) = 2.7 * 10 ^ 7 J / kg.

The mass of water that can be heated by burning 200 g of alcohol is determined from the equation: Sv * m1 * Δt = q * m2; m1 = q * m2 / (Sv * Δt).

Calculation: m1 = 2.7 * 10 ^ 7 * 0.2 / (4200 * 80) ≈ 16 kg.

Answer: By burning 200 grams of alcohol, you can heat 16 kilograms of water.

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