How much water is needed to prepare 160 grams of a 3% solution?

First, we calculate the mass of the solution
We know the following formula:
W = m / M p.ra
0.03 = x / 160
further Express x and get the following solution:
x = 0.03 × 160 = 4.8 g of substance
Next, we calculate the mass of water, for this we subtract the mass of the solution from the total mass and the result is the following solution:
m (H2O) = m – m p – pa = 160 – 4.8 = 155.2 g of water
This means that 155.2 grams of water is needed to prepare this solution.
Answer: 155.2 g of water is needed to prepare this solution.