How much water is required to dissolve sodium oxide weighing 24.8 grams.

univerkov | January 17, 2021 | education

Given:
m (Na2O) = 24.8 g
To find:
V (H2O)
Decision:
Na2O + H2O = 2NaOH
n (Na2O) = m / M = 24.8 g / 62 g / mol = 0.4 mol
n (Na2O): n (H2O) = 1: 1
n (H2O) = 0.4 mol
V (H2O) = n * Vm = 0.4 mol * 22.4 L / mol = 8.96 L
Answer: 8.96 L

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