How much water is taken at a temperature of 20 degrees in 10 minutes to a temperature of 100

How much water is taken at a temperature of 20 degrees in 10 minutes to a temperature of 100 degrees using a 48 ohm boiler? Mains voltage 127 V

We express the mass of water heated by a boiler from the equality: U ^ 2 * t / R = Cw * m * (t2 – t1), whence m = U2 * t / (R * Cw * (t2 – t1)).
Variables and constants: U – mains voltage (U = 127 V); t is the operating time of the boiler (t = 10 min = 600 s); R – resistance (R = 48 Ohm); Cw – heat capacity of water (Cw = 4200 J / (kg * K)); t2 – final temperature (t2 = 100 ºС); t1 – initial temperature (t1 = 20 ºС).
Calculation: m = U ^ 2 * t / (R * Cw * (t2 – t1)) = 127 ^ 2 * 600 / (48 * 4200 * (100 – 20)) = 0.6 kg.