How much water should be evaporated from 10 L of 0.35 M Н3РО4 solution to obtain a solution with a molar

How much water should be evaporated from 10 L of 0.35 M Н3РО4 solution to obtain a solution with a molar concentration of 6 mol / L?

In accordance with the condition, 10 liters of a 0.35 M solution of H3PO4 contain n = C1 * V1 = 0.35 * 10 = 3.5 moles of the substance.

From this amount of phosphoric acid, the following volume of solution with a molar concentration of 6 mol / l can be obtained: V2 = n / C2 = 3.5 / 6 = 0.583 liters.

All the rest of the water, namely 10 – 0, 583 = 9, 417 liters, must be removed, possibly evaporated.

Answer: You need to evaporate 9.417 liters of water.



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