How much water taken at a temperature of 20 can be brought to a boil by pouring 1 kg of tin into it at a temperature of 232.

Data: tv (initial water temperature) = 20 ºС; t (end temperature of water and tin) = 100 ºС; mo (mass of tin) = 1 kg; tо (initial temperature of tin, temperature of crystallization) = 232 ºС.

Constants: Sv (heat capacity of water) = 4200 J / (kg * K); Co (heat capacity of tin) = 230 J / (kg * K); λ (heat of crystallization of tin) = 0.59 * 105 J / kg.

Formula: Cw * mw * (t – tb) = mo * (λ + Co * (tо – t)), whence mw = mo * (λ + Co * (tо – t)) / (Cw * (t – tв )).

Calculation: mw = 1 * (0.59 * 105 + 230 * (232 – 100)) / (4200 * (100 – 20)) = 0.266 kg.