How much water, taken at a temperature of 20 degrees, can be converted into steam, spending 50%

How much water, taken at a temperature of 20 degrees, can be converted into steam, spending 50% of the heat released during the combustion of 40 g of kerosene.

Initial data: t0 (temperature before heating) = 20 ºС; m2 (mass of kerosene) = 40 g = 0.04 kg; η (efficiency) = 50% = 0.5.

Reference values: tboil (boiling point) = 100 ºС; C (specific heat) = 4200 J / (kg * K); L (specific heat of vaporization) = 2.3 * 10 ^ 6 J / kg; q (specific heat of combustion of kerosene) = 46 * 10 ^ 6 J / kg.

η = m1 * (C * (tboil – t0) + L) / (q * m2).

m1 = η * q * m2 / (C * (tboil – t0) + L) = 0.5 * 46 * 10 ^ 6 * 0.04 / (4200 * (100 – 20) + 2.3 * 10 ^ 6 ) = 0.349 kg or 349 g.