How much water vapor, the temperature of which is 100C, must be introduced into a brass calorimeter

How much water vapor, the temperature of which is 100C, must be introduced into a brass calorimeter with a mass of 100 g, in which there is snow of a mass of 150 g. at a temperature of minus 20C in order for all the snow to melt. The specific heat capacity of ice is 2100 J / kg. C, the specific heat capacity of brass is 380 J / kg C, and the specific heat of melting of ice is 3.4 10 to the fifth power J / kg. The specific heat of vaporization of water is 2.3×10 to the sixth power J / kg.

t1 = 100 “C.
t2 = – 20 “C.
t3 = 0 “C.
mk = 100 g = 0.1 kg.
Csn = 2100 J / kg * “C.
ml = 150 g = 0.15 kg.
Cl = 380 J / kg * “C.
ql = 3.4 * 10 ^ 5 J / kg.
λ = 2.3 * 10 ^ 6 J / kg.
mp -?
Qп = Qсн.
Qп = λ * mp.
Qsn = Csn * ml * (t2 – t3) + ql * ml + Cl * mk * (t2 – t3).
Csn * ml * (t2 – t3) + ql * ml + Cl * mk * (t2 – t3) = λ * mp.
mp = (Csn * ml * (t2 – t3) + ql * ml + Cl * mk * (t2 – t3)) / λ.
mp = (2100 J / kg * “C * 0.15 kg * (0” C – (-20 “C) + 3.4 * 10 ^ 5 J / kg * 0.15 kg + 380 J / kg *” C * 0.1 kg * (0 “C – (-20” C)) / 2.3 * 10 ^ 6 J / kg = 0.025 kg.
Answer: you need to enter mp = 0.025 kg of water vapor into the calorimeter.