How much will 1 kg of water heat up if you spend 42 Joules of energy.

Given:

m = 1 kilogram is the mass of water;

Q = 42 kJ – energy spent on heating water;

c = 4200 J / (kg * C) – specific heat of water.

It is required to determine dt (degree Celsius) – how many degrees water of mass m will be heated.

Let’s convert the units of measurement of energy into the SI system:

Q = 42 kJ = 42 * 103 = 42 * 1000 = 42000 Joules.

To determine the change in water temperature, you must use the following formula:

Q = c * m * dt, from here we find that:

dt = Q / (c * m) = 42000 / (4200 * 1) = 42000/4200 = 10 ° Celsius.

Answer: The water will heat up 10 ° Celsius.