How much will 2kg of water heat up if you tell it 50.4kJ of heat?

Initial data: m (mass of water) = 2 kg; Q (the amount of heat transferred to the water) = 50.4 kJ = 50.4 * 10 ^ 3 J.

Reference data: according to the condition Sv (specific heat capacity of water) = 4200 J / (kg * ºС).

The change in water temperature can be expressed from the formula: Q = Cw * m * Δt, whence Δt = Q / (Cw * m).

Calculation: Δt = 50.4 * 10 ^ 3 / (4200 * 2) = 6 ºС.

Answer: The water will be heated by 6 ºС.



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