How much will the internal energy of 10 kg of ice taken at a temperature of 0 degrees increase as a result

How much will the internal energy of 10 kg of ice taken at a temperature of 0 degrees increase as a result of its transformation into steam having a temperature of 100 degrees?

Data: m (ice mass) = 10 kg; t0 (initial ice temperature) = 0 ºС; t (temperature of the obtained steam) = 100 ºС.

Constants: λ (specific heat of melting of ice) = 3.4 * 10 ^ 5 J / kg; C (specific heat capacity of water) = 4200 J / (kg * K); L (specific heat of vaporization of water) = 23 * 10 ^ 5 J / kg.

The increase in the internal energy of ice is determined by the formula: Q = Q1 + Q2 + Q3 = λ * m + C * m * (t – t0) + L * m = m * (λ + C * (t – t0) + L) = 10 * (3.4 * 10 ^ 5 + 4200 * 100 + 23 * 10 ^ 5) = 30.6 * 10 ^ 6 J = 30.6 MJ.