How much will the internal energy of 200 g of helium change with an increase in temperature by 60K.

univerkov | December 14, 2020 | education

U = 3/2 vRT = 3/2 * m / M * RT = 3/2 * 0.2 / 0.004 * 8.31 * 60 = 37395 J = 37.395 kJ = 37.4 kJ
M helium = 0.004 kg / mol (found in the periodic table)
Answer: U = 37.4 kJ.

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