How much will the potential energy of a 2.5 kg stone change when it is lowered by 5m?

Given:

m = 2.5 kilograms – the mass of a certain stone;

h = 5 meters – the height to which the stone was lowered;

g = 10 N / kg (Newton per kilogram) – acceleration due to gravity (rounded off).

It is required to determine dE (Joule) – how much the potential energy of the stone will change when it is lowered to a height of h.

Since, according to the condition of the problem, the height of the stone was reduced, its potential energy will also decrease by a value equal to:

dE = m * g * h = 2.5 * 10 * 5 = 25 * 5 = 125 Joules.

Answer: when the stone is lowered by 5 meters, its potential energy will decrease by an amount equal to 125 Joules.