How much will the pressure on the bottom of the beaker increase if you add 60 g of water to it?

How much will the pressure on the bottom of the beaker increase if you add 60 g of water to it? The bottom area of the beaker is 12 cm²

Data: m (mass of added water) = 60 g = 0.06 kg; S (bottom area of the beaker) = 12 cm2 = 12 * 10-4 m2.

Constants: ρ (water density) = 1000 kg / m3; g (acceleration due to gravity) = 10 m / s2.

1) The volume of water added to the beaker: V = m / ρ = 0.06 / 1000 = 0.06 * 10-3 m3.

2) Increase in the water level in the beaker: Δh = V / S = 0.06 * 10-3 / (12 * 10-4) = 0.05 m.

3) Increase in pressure at the bottom of the beaker: ΔР = ρ * g * h = 1000 * 10 * 0.05 = 500 Pa.

Answer: The water pressure at the bottom of the beaker will increase by 500 Pa.