Initial data: Q (energy transferred to a piece of lead) = 2800 J, m (mass of a piece of lead) = 2 kg.
Constants: C (specific heat capacity of lead) = 140 J / (K * kg).
Formula for calculations:
Q = C * m * Δt.
Δt = Q / (C * m).
Let’s perform the calculation:
Δt = 2800 / (140 * 2) = 2800/280 = 10 ° C.
Answer: The temperature of a piece of lead will rise by 10 ° C.
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