How much will the temperature of a piece of lead with a mass of 2 kg change if energy equal to 2800 J is transferred to it?

Initial data: Q (energy transferred to a piece of lead) = 2800 J, m (mass of a piece of lead) = 2 kg.

Constants: C (specific heat capacity of lead) = 140 J / (K * kg).

Formula for calculations:

Q = C * m * Δt.

Δt = Q / (C * m).

Let’s perform the calculation:

Δt = 2800 / (140 * 2) = 2800/280 = 10 ° C.

Answer: The temperature of a piece of lead will rise by 10 ° C.

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