How much will the temperature of a steel part with a mass of 500 g rise, if the amount of heat is transferred to it 6.9 kJ.

Problem data: m (weight of the steel part under consideration) = 500 g (0.5 kg); Q (the amount of heat transferred to the steel part) = 69 kJ (6900 J).

Reference values: Cc (specific heat capacity of steel) = 460 J / (kg * K).

The temperature rise of the steel part under consideration is expressed from the formula: Q = Cc * m * Δt, whence Δt = Q / (Cc * m).

Calculation: Δt = 6900 / (460 * 0.5) = 30 ºС.

Answer: The temperature of the steel part in question will rise by 30 ° C.



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