How much will the temperature of the water in a vessel containing 200 g of water change if a 100 C

How much will the temperature of the water in a vessel containing 200 g of water change if a 100 C charge has passed through the conductor placed in it, and a voltage of 20 V is applied to the ends of the conductor? specific heat capacity of water 4.2 kJ / (kg K)

m = 200 g = 0.2 kg.

C = 4.2 kJ / kg * K = 4200 J / kg * K.

q = 100 Cl.

U = 20 V.

Δt -?

Let us express the amount of heat Q that is required for heating water: Q = C * m * Δt, where C is the specific heat capacity of water, m is the mass of heated water, Δt is the change in water temperature.

When current passes through the conductor, the amount of heat Q is released, which is expressed by the Joule-Lenz law: Q = I * U * T, where I is the current strength, U is the voltage, T is the time of current passage.

According to the definition, the current strength I is determined by the formula: I = q / T, where q is the charge that has passed, T is the time of passage of the charge.

Q = q * U * T / T = q * U.

C * m * Δt = q * U.

Δt = q * U / C * m.

Δt = 100 C * 20 V / 4200 J / kg * K * 0.2 kg = 2.4 K.

Answer: the water temperature in the vessel will increase by Δt = 2.4 K.