How much will the temperature of water weighing 20 kg change if all the energy released

How much will the temperature of water weighing 20 kg change if all the energy released during the combustion of 20 g gasoline is transferred to it?

Given: mw (mass of water) = 20 kg; mb (mass of burnt gasoline) = 20 g (0.02 kg).

Constants: Sv (specific heat capacity of water) = 4200 J / (kg * ºС); qb (specific heat of combustion of kerosene) = 46 * 10 ^ 6 J / kg.

We express the change in the temperature of the taken water from the equality: Sv * mw * Δt = mb * qb, whence Δt = mb * qb / (Sv * mw).

Let’s make the calculation: Δt = 0.02 * 46 * 10 ^ 6 / (4200 * 20) = 10.95 ºС.

Answer: The temperature of the taken water will rise by 10.95 ºС.