How much will the temperature of water with a volume of 100 liters change,

How much will the temperature of water with a volume of 100 liters change, if, assuming that all the heat released when burning charcoal weighing 0.5 kg will go to heating the water.

Data: V (volume of water taken) = 100 l (0.1 m3); m2 (mass of charcoal burnt) = 0.5 kg; all the heat from burning charcoal went to heating water.

Constants: ρ (density of the taken water) = 1000 kg / m3; С (specific heat capacity of water) = 4200 J / (kg * ºС); q (specific heat of combustion of charcoal) = 34 * 106 J / kg.

The change in temperature of 100 liters of water is determined from the ratio: C * ρ * V * Δt = q * m2, whence Δt = q * m2 / (C * ρ * V).

Δt = 34 * 106 * 0.5 / (4200 * 1000 * 0.1) = 40.48 ºС.