How much will the temperature of water with a volume of 300 ml change, if it receives all the energy

| August 9, 2021 | education

How much will the temperature of water with a volume of 300 ml change, if it receives all the energy released when cooling a lead cylinder weighing 0.21 kg from a temperature of 120C to a temperature of 20C

Data: V (volume of water) = 300 ml (300 * 10-6 m3); m2 (mass of the lead cylinder) = 0.21 kg; t1 (initial temperature of the cylinder) = 120 ºС; t2 (final cooling temp.) = 20 ºС.

Constants: ρ (water density) = 1000 kg / m3; Sv (specific heat capacity of water) = 4200 J / (kg * ºС); Ссв (specific heat capacity of lead) = 140 J / (kg * ºС).

We calculate the change in water temperature from the equality: Sv * ρ * V * Δt = Сw * m2 * (t1 – t2) and Δt = Сw * m2 * (t1 – t2) / (Sv * ρ * V) = 140 * 0.21 * (120 – 20) / (4200 * 1000 * 300 * 10-6) = 2.33 ºС.



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