How much will the water temperature change if all the energy released during the combustion of 10 g

How much will the water temperature change if all the energy released during the combustion of 10 g kerosene is spent on heating 22 kg water? q (kerosene) = 46 * 10 ^ 6 J \ kg

We give all the values ​​from given in the SI system:
mt = 10g = 0.01 kg.
1. The amount of heat spent on heating the body is equal to the product of the specific heat capacity of the substance, body weight and the difference between the final and initial temperatures.
Q = c * m * ∆t, where c is the specific heat capacity of the substance, m is the mass of the substance, ∆t is the temperature change.
Specific heat of water according to the reference book c = 4200 J / kg * K.
2. During the combustion of fuel, the amount of heat will be released:
Qg = q * mt, where q is the specific heat of combustion of the fuel, m is the mass of the substance.
Specific heat of combustion of gasoline q – 46 * 10 ^ 6 J / kg.
3. Since we have spent all the heat for heating, we will equate the amounts of heat:
Qg = Q.
q * mt = c * m * ∆t, we express the temperature change from this expression:
∆t = (q * mt) / (c * m).
4. Substitute the numerical values, we get:
∆t = (q * mt) / (c * m) = (46 * 10 ^ 6 * 0.01) / (4200 * 22) = 4.98 ° C.
Answer: 4.98 ° C.