How much will the weight of an iron bar 1.2 m long, 7 dm wide and 40 cm thick decrease in kerosene?

l = 1.2 m.
b = 7 dm = 0.7 m.
d = 40 cm = 0.4 m.
ρ = 800 kg / m ^ 3.
g = 9.8 m / s ^ 2.
ΔР -?
ΔР = Farch.
Farch = ρ * g * V.
V = l * b * d.
ΔР = ρ * g * l * b * d.
ΔР = 800 kg / m ^ 3 * 9.8 m / s ^ 2 * 1.2 m * 0.7 m * 0.4 m = 2634.24 N.
Answer: ΔР = 2634.24 N.



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