How much wood does it take to boil 10 liters of water in a 1.5 kg aluminum bucket?

Given:
s (al) = 920 J / kg * ° С
c (c) = 4200 J / kg * ° С
V (c) = 10 L = 0.01 m ^ 3
m (al) = 1.5 kg
q (d) = 10000000 J / kg
t1 = 0
t2 = 100
ρ (w) = 1000 kg / m ^ 3
Find m (q) =?
Decision:
The total amount of heat is the sum of the amount of heat from heating the water and heating the pan
Q = Q (in) + Q (al)
Q = cm (t2-t1)
m = ρV
m (c) = 1000 kg / m ^ 3 * 0.01 m ^ 3 = 10 kg
Q (c) = 4200 J / kg * C * 10 kg * (100-0 ° C) = 4200000 J
Q (al) = 920 J / kg * ° C * 1.5 kg * (100-0 ° C) = 138000 J
Q = 4200000 J + 138000 J = 4338000 J
The amount of heat from the combustion of wood is equal to the amount of heat from heating the pan and water
Q = Q (q)
Q (q) = qm hence m = Q / q
m = 4338000 J / 10000000 J / kg = 0.4338 kg ≈0.5 kg
Answer: m (d) = 0.5 kg