How much would 16 g SO2 take under normal conditions?

univerkov | September 23, 2021 | education

Given:

m (SO2) = 16 g.

V (SO2) -?

Solution:

Find the volume of sulfur (IV) oxide SO2.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

n = m: M.

M (SO2) = 64 g / mol.

n = 16 g: 64 g / mol = 0.25 mol.

V = 0.25 mol × 22.4 L / mol = 5.6 L.

Answer: 5.6 liters.

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